If calcium hardness is 3.2 gpg and magnesium hardness is 8.5 gpg, what is the total hardness in mg/l?

To determine the total hardness in mg/l from the provided calcium hardness and magnesium hardness values, we must first convert the hardness measurements from grains per gallon (gpg) to milligrams per liter (mg/l).

1. The conversion factor from gpg to mg/l is approximately 17.1. This means that for every 1 gpg, there are approximately 17.1 mg/l.

2. First, we convert the calcium hardness:

   • Calcium hardness = 3.2 gpg
   • 3.2 gpg × 17.1 mg/l = 54.72 mg/l

3. Next, we convert the magnesium hardness:

   • Magnesium hardness = 8.5 gpg
   • 8.5 gpg × 17.1 mg/l = 145.35 mg/l

4. The total hardness is then calculated by adding both converted values together:

   • Total hardness = Calcium hardness + Magnesium hardness
   • Total hardness = 54.72 mg/l + 145.35 mg/l = 200.07 mg/l

Thus, the total hardness comes out to be 200.07 mg/l. This makes the correct answer consistent with the calculations and aligns with